Im pretty bad in math could somebody help me please

1st, you need to do the exponent (im talking about the 3) that's the exponent you need to multiply so multiply 2 but 3 times so 2× 2 = 4 then 4×2 = 8 then 8× 2= 16 now it should be like this

42 ÷ 7 × 2 - 16 + 6

now let's multiply 7 × 2 which is 14 so it will look like this

42 ÷ 14 - 16 + 6

now divide 42 and 14 and you will get 3 so like this

3 - 16 + 6

now subtract 3 from 16 and that is 13

13 + 6

and you have 19 there you go

I really hope this helps:)

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

idk

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