If Z= 2+2i, what is z^4?

D. 64 (cos(pi)+isin(pi))

Step-by-step explanation:

Put 2+2i into trigonometric form, raise the r value to the power of 4, and multiply the angle value (theta) by 4 to get the equation of z^4. In this case, r was 2(sqrt2), which raised to the 4th power was 64. The angle value was pi/4, which multiplied by 4 was pi. That's how we get the

64 (cos(pi)+isin(pi)). How this helps!

dude thats to long figure it

step-by-step explanation:

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