Mathematics, 02.12.2020 01:00 glander2
A display has 666 packs of marbles with a total mass of 629\,\text{g}629g629, start text, g, end text. The packaging of each pack has a mass of \dfrac{2}{3}\,\text{g}
3
2
gstart fraction, 2, divided by, 3, end fraction, start text, g, end text and each marble has a mass of 4\dfrac{1}{2}\,\text{g}4
2
1
g4, start fraction, 1, divided by, 2, end fraction, start text, g, end text.
Which equation can we use to determine mmm, the number of marbles per pack?
Choose 1
Choose 1
(Choice A)
A
6\cdot 4\dfrac{1}{2}m+\dfrac{2}{3}=6296⋅4
2
1
m+
3
2
=6296, dot, 4, start fraction, 1, divided by, 2, end fraction, m, plus, start fraction, 2, divided by, 3, end fraction, equals, 629
(Choice B)
B
6m\left(4\dfrac{1}{2}+\dfrac{2}{3}\ right)=6296m(4
2
1
+
3
2
)=6296, m, left parenthesis, 4, start fraction, 1, divided by, 2, end fraction, plus, start fraction, 2, divided by, 3, end fraction, right parenthesis, equals, 629
(Choice C)
C
6m+4\dfrac{1}{2}+\dfrac{2}{3}=6296m +4
2
1
+
3
2
=6296, m, plus, 4, start fraction, 1, divided by, 2, end fraction, plus, start fraction, 2, divided by, 3, end fraction, equals, 629
(Choice D)
D
6\left(4\dfrac{1}{2}m+\dfrac{2}{3}\ right)=6296(4
2
1
m+
3
2
)=629
Answers: 2
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