The perimeter of a rectangle is 52 feet. The length is 2 more than twice the width. What is the length of the rectangle?

 The Length of the rectangle is 18 feet.

The width is 8 feet

Step-by-step explanation:  Perimeter is 2w + 2L

Length here is 2w + 2   Substitute this value for L in the equation.

P = 2w + 2L

52 = 2w + 2(2w + 2)  distribute and add

52 = 2w + 4w + 4

52 = 6w + 4    Subtract 4 from both sides, Then divide both sides by 6 to solve  for w

48 = 6w

8 = w  The width is 8 ft

Substitute into the original expression for Length

Length here is 2w + 2 :  2(8) + 2   16 + 2 = 18

The Length is 18 feet.

Check:   in the original equation P = 2w + 2L

52 = 2(8) + 2(18)

52 = 16 + 36  TRUE!

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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