Whats the equation for a line thats perpendicular to 6x-2y=8 when it passes through (6,-5) ( i hope i wrote that right sorry)

Equation of required line is:

Step-by-step explanation:

We need to find equation for a line that's perpendicular to when it passes through (6,-5)

We will use the slope-intercept form: where m is slope and b is y-intercept.

Finding Slope m:

When two lines are perpendicular there slopes are

Finding slope of given equation first:

Writing in slope-intercept form:

Comparing it with slope intercept form: , m= 3

So, slope of given equation is 3

Now, the slope of required equation will be

So, Slope m=-1/3

Finding y-intercept

Using slope m=-1/3 and point (6,-5) we can find y-intercept

So, y-intercept is b=-3

Now, finding the equation of required line having Slope m=-1/3 and y-intercept b= -3

Writing in standard form:

So, equation of required line is:

26

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²