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Mathematics, 01.12.2020 19:00 savvaggeb
Solve the following equation algebraically:
-16 = 16x^2 How many solutions does this equation have? Explain.
a. -1=x^2: One solution because only -1 will satisfy the equation.
b. -1=x^2: No real solution because there is no real number that, when squared, produces -1.
C. 1=x^2: Two solutions because the square root of 1 is positive 1 and negative 1.
d. 1=-x^2: One solution because only -1 will satisfy the equation.
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Solve the following equation algebraically:
-16 = 16x^2 How many solutions does this equation have?...
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