HELP PLEASE If triangle PQR is plotted, it will have the following coordinates, P(-4,0),Q(4,2)and R(-2,4). If point R is translated 4 units right and 7, what are the coordinates of R'?

(2, -3)

Step-by-step explanation:

Right now, R is at (-2, 4). If it is pushed 4 units to the right, it becomes -2+4 = 2 on the x-axis. If it is pushed 7 units down, it becomes 4-7 = -3. Thus, the coordinates are (2, -3)

A triangle has vertices A(-3,6), B(-3, 4), and C(3,4).

If the triangle is translated 2 units to the right and 1 unit down, what will be the new coordinates of vertex A?

(-1, 5)

Step-by-step explanation:

Right now, A is at (-3, 6). If it is pushed 2 units to the right, it becomes -3+2 = -1 on the x-axis. If it is pushed 1 unit down, it becomes 6-1 = 5. Thus, the coordinates are (-1, 5)

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.