HELP FAST WILL GIVE BRAINLIEST AND 5 STARS ALSO 30 POINTS! Select the correct answer.
Which sequence of transformations proves that shape I is similar to shape II?
A. a 90° counterclockwise rotation about the origin, and then a dilation by a scale factor of 2
B. a reflection across the x-axis, and then a dilation by a scale factor of 3
C. a reflection across the x-axis, and then a dilation by a scale factor of 2
D. a 90° counterclockwise rotation about the origin, and then a dilation by a scale factor of 3

 C. a reflection across the x-axis, and then a dilation by a scale factor of 2

Step-by-step explanation:

We see that the shapes are on the opposite sides of the x-axis, and vertical lines are still vertical.  A 90° rotation would have made the vertical lines horizontal.

We see that the line that was 1 unit long is now 2 units. The line that went from 4 to 6 goes from 8 to 12. This is evidence of a dilation bt a factor of 2.

25

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.