Write an equation for the line, in STANDARD form, that passes through (1, 3) and (5, -2)

One standard form of a line is the slope-intercept:

y = m*x + b

In this form m is the slope of the line and b is the value of y when x is zero( that is the value of y where the line crosses the y-axis).

In this case m = -3/5 so we have:

y = (-3/5)*x + b

Since the line passes through the point (7,-11) we know that when x = 7,

y = -11.

So substituting in the equation above we have:

-11 = (-3/5)*7 + b

-11 = -21/5 + b

b = 21/5 - 55/5 = -34/5

The equation of the line then is:

y = (-3/5)*x - 34/5

d≈7.07in

step-by-step explanation: