Clare knows that Priya has a bunch of nickels and dimes in her pocket and that the total amount is $1.25. Find one possibility for the number of nickels and number of dimes that could be in Priya's pocket. Write an equation that describes the relationship between the number of dimes and the number of nickels in Priya's pocket. Explain what the point (13,6) means in this situation. Is the point (13,6) a solution to the equation you wrote? Explain your reasoning.

5x + 10y = 125

Step-by-step explanation

Number of nickel = x

Number of dime = y

Nickel = 5 cent

Dime = 10 cent

Total value = $1.25

Total value should be converted to cent since both dime and nickel are both in cent

= $1.25 * 100 = 125 cents

Therefore,

5x + 10y = 125 cents

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2