The youth group is going on a trip to the state fair. The trip costs $62. Included in that price is $14 for a concert ticket and the cost of 2 passes, one for the rides and one for the game booths. Each of the passes costs the same price. Write an equation representing the cost of the trip, and determine the price of one pass. Solve your equation by showing your work and steps.

Step-by-step explanation:

62-14=48

62 is the total cost and if you minus $14 you will be left with $48 which will be the cost of the two passes

48/2=24.

48 is the cost of the two passes and you want to divide this by 2 to find the cost of one pass.

so, one pass equals $24

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°