Jim Gym, a high school basketball coach, wants to analyze the height of the boys at his school. He knows their height is normally distributed so he can use the standard normal distribution. He measures the height of 100 randomly selected boys. Next, he calculates the mean and standard deviation of their heights. The mean is 66 inches and the standard deviation is 5 inches. Jim uses the normal distribution table to calculate the number of boys in each segment of the distribution. Standard Deviation Percentage from table Number of boys out of 100
-2 to -1 (
to 61 inches)
% 14
-1 to 0 (61 to
inches) 34.1%
0 to +1 (66 to 71 inches)
%
+1 to +2 (71 to
inches) 13.6 %

step-by-step explanation:

i hate black

168

step-by-step explanation:

i am pretty sure that the answer is 168

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.