Which of the following statements is true about the graph of the inequality y≤ax+b, where a≠0? A. The graph of the inequality is a dashed line, and the shaded region is below the line.
B. The graph of the inequality is a solid line, and the shaded region is below the line.
C. The graph of the inequality is a solid line, and the shaded region is above the line.
D. The graph of the inequality is a dashed line, and the shaded region is above the line.

The correct option is;

B. The graph of the inequality is a solid line, and the shaded region is below the line

Step-by-step explanation:

The given inequality is y ≤ ax + b, a ≠ 0

Therefore. the inequality is a straight line graph with a slope = a, and a y-intercept of b

Given that the inequality uses an equal to or lesser than sign, we have that the graph of the inequality is a solid line

Whereby the region of feasibility is the region below the value of the expression on the right of the inequality, the area below the straight line graph is the shade (feasible) region.

answer: 1 and 3

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!