The school athletic director has a storage closet that 4 1/2 feet long, 2 2/3 feet deep, and 6 feet tall. a. She wants to put a carpet in the closet. How much carpeting will she need? b. The athletic director wants to store cube boxers that are 1/2 foot wide. How many boxers will the storage hold?

Answer and Explanation:

The closet is 4 1/2 feet long, 2 2/3 feet deep, and 6 feet tall

Since we are not given width of the closet, we assume the base of the closet has equal width and length = 4 1/2 feet(closet base is a square)

Closet is 2 2/3 feet deep and 6 feet tall, therefore closet height internal = 8 2/3 feet

a. How much carpeting will she need?

The carpeting needed for the closet = area of base of the closet(square base)= 4 1/2* 4 1/2 = 4.5*4.5= 20.25 square feet

b. The athletic director wants to store cube boxers that are 1/2 foot wide. How many boxers will the storage hold?

Area of base = 20.25

Area of base of each cube on the floor = 0.5*0.5= 0.25

So we know that the base of the closet will hold

20.25/0.25= 81 boxer cubes

Or we could straight to the point

Find volume of the closet( the closet is clearly a cuboid) and divide by the volume of one cube to find number of cubes that will fit into the closet

Volume of the closet/cuboid = l*w*h =4.5*4.5*8.67/0.25

=702.27

Therefore number of boxer cubes to fit in closet= 702

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)

i can answer this question sweetie!

step-by-step explanation: