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Step-by-step explanation:

Remark

If the horizontal lines are parallel, then 2x +  20 = 3x - 10

Equation

2x + 20 = 3x - 10

Add 10 to both sides

2x + 20 + 10 = 3x

Subtract 2x from both sides

30 = x

2x + 20 = 2*30 + 20 = 80

x = 30 and both the angles are 80°

In the given figure,

∠(2x + 20) = ∠(3x - 10)             [corresponding angles]

20 = x - 10                                [subtracting 2x from both sides]

x = 30                                      [adding 10 on both sides]

Value of the angles:

the questions required us to find the measure of a certain ∠XAE, but since we cannot see an ∠XAE in the image provided, we will find the measure of both the angles     [let ∠(2x + 20) = ∠1     and     ∠(3x-10) = ∠2]

Measure of ∠1:

We are given that the magnitude of ∠1 is:

∠1 = 2x + 20

since x = 30

∠1 = 2(30) + 20                             [replacing the value of x]

∠1 = 80°

Measure of ∠2:

We are given that the magnitude of ∠2 is:

∠2 = 3x - 10

since x = 30

∠2 = 3(30) - 10                              [replacing the value of x]

∠2 = 80°