What is an equation of the line that passes through the points (3,4) and (−4,−3)? Put your answer in fully reduced form

The equation of the line is y = x + 1

Step-by-step explanation:

The equation of the line is y = m x + b, where

The rule of the slope of the line is m = , where

∵ The line passes through points (3, 4) and (-4, -3)

∴ x1 = 3 and y1 = 4

∴ x2 = -4 and y = -3

→ Substitute them in the rule of the slope above to find it

∵ m = = = 1

∴ m = 1

→ Substitute it in the form of the equation above

∴ y = 1(x) + b

∴ y = x + b

→ To find b substitute x by 3 and y by 4 in the equation

∵ 4 = 3 + b

→ Subtract 3 from both sides

∵ 4 - 3 = 3 - 3 + b

∴ 1 = b

→ Substitute it in the equation

∴ y = x + 1

∴ The equation of the line is y = x + 1

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

hi there!

the answer will be d: 2