PLEASE HELP ME Slowhan decides to play a very fun game. He starts off with his favorite
odd integer. For every turn, Slowhan will either add 1 or subtract 1 to his current number.
What is the probability that after 11 turns, the resulting number will be odd?

Answer is even on the 11th turn unless Slowhan is allowed to skip a turn.

Step-by-step explanation:

If you add or subtract every turn then every turn will always be the opposite of the last turn, so, it would be.

odd is 0

1 = even

2 = odd (You've seen here that every even numbers of turns how answer will be odd and when it is an odd number of turns it will be even)

3 = even

4 = odd

5 = even

6 = odd

7 = even

8 = odd

9 = even

10 = odd

11 = even

i'm sorry i don't know

step-by-step explanation:

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you