What is wrong with the equation? 3 x−5 dx = x−4 −4 3 −1 = 20 81 −1 There is nothing wrong with the equation. f(x) = x−5 is continuous on the interval [−1, 3] so FTC2 cannot be applied. The lower limit is less than 0, so FTC2 cannot be applied. f(x) = x−5 is not continuous on the interval [−1, 3] so FTC2 cannot be applied. f(x) = x−5 is not continuous at x = −1, so FTC2 cannot be applied.

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answer: plz give a pic and answer choices so i can answer!

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.