Given RT below, if S lies on RT such that the ratio of RS to ST is 3:1, find the coordinates of S.

S(-2, -3)

Step-by-step explanation:

Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;

S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;

x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1

Substitute the values into the formula;

X = ax2+bx1/a+b

X = 3(-1)+1(-5)/3+1

X = -3-5/4

X = -8/4

X = -2

Similarly;

Y = ay2+by1/a+b

Y = 3(-5)+1(3)/3+1

Y = -15+3/4

Y = -12/4

Y = -3

Hence the coordinate of the point (X, Y) is (-2, -3)

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

9x