A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky.
His annual interest is 10626 dollars. How much did he invest at each rate?
Your answer is
total in the account paying 6 percent interest is
total in the account paying 10 percent interest is

aloha~! my name is zalgo and i am here to you out on this gracious day. in order to compare the ratios easily, it is best that we simplify the question first. so, the cougars would have 6 wins for 5 losses, bobcats make 2 wins for 1 loss. bulldogs and tigers have a ratio where you can't simplify it. so, the team with the lowest rate would be the bobcats.

i hope that this ! : d

"stay and stay proud! " - zalgo

about 0.75 hours

step-by-step explanation:

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)

тgє qυєѕтισи αѕкє∂: ιи тнє ѕєяιєѕ σя яєα¢тισиѕ тgαт σ¢¢υя ιи ρнσтσѕуитнєѕιѕ, ωнι¢н fσямѕ ωнєи ℓιgнт ѕтяιкєѕ α мσℓє¢υℓє σf ¢нℓσяσρнуℓℓ.

α. мσℓє¢υℓє σf ωαтєя

в.тнєє-¢αявσи ѕυgαя

¢. "єχ¢ιтє∂" єℓє¢тяσи

∂. иα∂ρн

му αиѕωєя: ιт ιѕ ¢. "єχ¢ιтє∂" єℓє¢тяσи

нσρє ι ¢συℓ∂ нєℓρ υ