Fredrick threw a ball from the top of a building. The height of the ball, in feet, after it is thrown is modeled by the function h(t) = –1672 +64t + 100, where represents time, in seconds.

Approximately how long did it take the ball to reach the ground (h=0)?

5.2seconds

Step-by-step explanation:

Fredrick threw a ball from the top of a building. The height of the ball, in feet, after it is thrown is modeled by the function

The modeled function is given as

h(t) = –16t^2 +64t + 100,

We can see this is a quadratic equation, we can solve using quadratic formula, Below

= -b±(√b^2 -4ac)/2a

Where

a=-16, b=64, c=100

FROM THE ATTACHMENT

We have too answers t= -1.20s and t=5.20s

Therefore,it take 5.20s for the ball to reach the ground (h=0). Because "t" cannot be negative here

CHECK THE ATTACHMENT FOR THE QUADRATIC SOLUTION

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x