SOmeone SMART HELP ME OMG

x = 7, arc DE = 198°

Step-by-step explanation:

Inscribed angles from the same arc are congruent.

∠ DCE and ∠ DWE are inscribed angles from the same arc DE , thus

12x + 15 = 3x + 78 ( subtract 3x from both sides )

9x + 15 = 78 ( subtract 15 from both sides )

9x = 63 ( divide both sides by 9 )

x = 7

Thus

∠ DCE = 12x + 15 = 12(7) + 15 = 84 + 15 = 99°

The inscribed angle DCE is half the measure of its intercepted arc, thus

arc DE = 2 × 99° = 198°

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

entering that problem on the tube might get you an answer