two glasses of milk and 3 snack bars have a total of 78 carbohydrates (carbs), and 4 glasses of milk and 3 snack bars have a total of 96 carbs. Determine how many carbs are in one glass of milk and in one snack bar

Each glass of milk is 9 carbs.

Each snack bar is 19.7 carbs.

Step-by-step explanation:

1. I know that 2 glasses of milk with 3 snack bars is 78 carbs.

The next part of the sentence has two times the amount of milk with the same amount of snack bars for 96 carbs.

Now, I will find the difference in the amount of carbs.

96 - 78 = 18 carbs.

So two glasses of milk = 18 carbs.

18 ÷ 2 = 9 carbs

So, each glass of milk is 9 carbs.

2. Since we know this, we can subtract the amount of carbs from the glasses of milk from the total amount of carbs.

78 - 19 = 59

In the first scenario, there are 59 carbs per 3 snack bars.

To find the amount of each snack bar, divide 59 by 3.

59 ÷ 3 = 19.7 when rounded to the nearest tenth.

Therefore, each snack bar is 19.7 carbs.

glass of milk = 9 carbohydrates

snack bars = 20 carbohydrates

Step-by-step explanation:

Let s be snack bars and g be the glasses of milk.

3s + 2g = 78

3s + 4g = 96

-1(3s + 2g) = -1(78)

- 3s - 2g = - 78

- 3s - 2g = - 78

3s + 4g = 96

2g = 18

g = 18/2

g = 9

3s + 2g = 78

3s + 2(9) = 78

3s + 18 = 78

3s = 78 - 18

3s = 60

3s/3 = 60/3

s = 20

Check: g = 9; s = 20

3s + 2g = 78

3s + 4g = 96

3(20) + 2(9) = 78

60 + 18 = 78

78 = 78

3(20) + 4(9) = 96

60 + 36 = 96

96 = 96

So, the solution is g = 9; s = 20

answer: sensy

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."