Please help work late! System applications please show me your work! 4. The perimeter of a rectangle is 56 centimeters. The length of the rectangle is 2 centimeters more than
the width. Find the dimensions of the rectangle. (Hint: P = 21 + 2w)
I

The rectangle has a length of 15 cm and a width of 13 cm

Step-by-step explanation:

Let w represent the width of the rectangle, and let w + 2 represent the length of the rectangle.

Use the perimeter formula, P = 2l + 2w, and plug in the perimeter and w + 2:

P = 2l + 2w

56 = 2(w + 2) + 2w

Simplify and solve for w:

56 = 2w + 4 + 2w

56 = 4w + 4

52 = 4w

13 = w

Then, add 2 to this to find the length:

13 + 2

= 15

So, the rectangle has a length of 15 cm and a width of 13 cm.

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s