Solve the following system by graphing. If there isn't a unique solution to the system, state the reason. y=-2x y=2x+4

We have the system of equations:

y = -2*x

y = 2*x + 4.

To solve it by graphing, you need to graph both lines and see in which point the lines intersect each other.

You can see it in the image below. (blue is y = 2*x + 4, and green is y = -2*x)

We also can calculate the solution with math, let's do that:

y = -2*x

y = 2*x + 4.

We can replace the first equation in the second one, to get:

-2*x = 2*x + 4

Now let's solve this for x

-2*x -2*x = 4

-4*x = 4

x = 4/-4 = -1

Evaluating this in one of the equations we get:

y = -2*-1 = 2

Then the solution is the point (-1, 2), exactly what we can see in the graph.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2