(x - 3)^2/9 - (y - 2)^2/16 = 1 The vertices of the hyperbola are:
(-1, 2) and (7, 2)
(3, 6) a...
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Mathematics, 29.11.2020 03:10 PearlJam5492
(x - 3)^2/9 - (y - 2)^2/16 = 1 The vertices of the hyperbola are:
(-1, 2) and (7, 2)
(3, 6) and (3, -2)
(0, 2) and (6, 2)
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