PLEASE HELP 1.) Line a passes through points (-2, 1) and (2, 9). Write an equation in slope intercept form that is parallel to line a. 40POINTS

y=2x

Step-by-step explanation:

compute the slope  first-

(-2,1) and (2,9)

m = 9-1/2-(-2) = 8/2+2= 8/4 = 2

knowing the slope take a given point  and substitute  it's x and y values into the equation to solve for 'b' the y-intercept-

y = mx + b,

1 = 2(-2) + b,

1 = -4+ b,

b = 5

our  equation is  y = 2x + 5

if you want an equation parallel  to the line  it  has to have the same slope. Take y = 2x

y=2x+5

Step-by-step explanation:

To find line a in slope-intercept form, we first want to find the slope. The formula for slope is .

Now that we know the slope, we can plug in any point to find the y-intercept.

y=2x+b       [plug in any point]

9=2(2)+b    [multiply]

9=4+b         [subtract both sides by 4]

b=5

The final equation is y=2x+5.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

(x+3)(x+7)

step-by-step explanation: