An asteroid and a planet are 383 000 km apart. The asteroid then travels 99 500 km towards the planet.
How far does the asteroid have left to travel before
it reaches the planet? Work it out in your head.

The asteroid are separated by 383,000 km.

The asteroid moves 99,500 km toward the planet.

Let F = how far does the asteroid need to travel before reaching the planet.

F = 383,000 km - 99,0m500 km

F = 283,500 km

Got it?

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

x = 23.78

step-by-step explanation: