How do I solve this radical and then check all the solutions?

This problem of equations involving surds can be solved by :

Firstly,square both sides of the equation to do away with the surd

(√x+3)²=(x-3)²

Next,we do away with the surd or let me put it as sign of square root and FOIL out the RHS

x+3=x²-6x+9

Rearranging leads to:

x²-6x-x+9-3=0

x²-7x+6=0 which factorises to:

(x-6)(x-1)=0

Finding the zeros leads to

x=6 or 1

We now conduct a test to see which value(s) of x satisfy the equation

√6+3=6-3

√9=3

3=3, so x=6 is true

Now for 1,

√1+3=1-3

√4 is not equal to -2

Therefore we conclude that x=6

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph