Travis made a business trip of 195.5 miles. He averaged

53 mph for the first part of the trip and

58 mph for the second part. If the trip took

3.5 hours, how long did he travel at each rate?

At 53 mph, he traveled for 1.5 hours

At 58 mph, he traveled for 2 hours

Step-by-step explanation:

Mathematically;

distance = speed * time

let the time for the first part of the trip be x hours and the second part be y hours

Total hours is 3.5

So therefore;

x + y = 3.5 ••••••••(i)

Now let’s work with the rate

53 mph for x hours = 53 * x = 53x miles

58 mph for y hours = 58 * y = 58y miles

Adding both;

53x + 58y = 195.5 miles ••••••••(ii)

We have two equations to solve simultaneously

From i, x = 3.5 - y

insert into ii

53(3.5-y) + 58y = 195.5

185.5 - 53y + 58y = 195.5

5y = 195.5-185.5

5y = 10

y = 10/5

y = 2 hours

x = 3.5 - y

x = 3.5 - 2

x = 1.5 hours

false

step-by-step explanation:

whenever we assume a point on a plane then according to geometry it will definitely have 2 dimensions and if it assumed in space then it will have 3 dimensions.

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450