A triangle has exactly three sides. Prove the conditional by proving the contrapositive. If a polygon has more than three sides, then it is not a triangle. Contrapositive: If , then . Since , the contrapositive is , the original statement must be .

Contrapositive: if a polygon does not have more than 3 sides, then it is a triangle. Since it is a true statement, the contrapositive is a true statement, the original statement must be a true statement.

Step-by-step explanation:

Original statement: if a polygon has more than three sides, then it is not a triangle.

Let P = a polygon has more than three sides

Let Q = it is not a triangle

Conditional statement: If P, then Q

Contrapositive statement: if not P, then not Q.

If a conditional statement is true, then the contrapositive is true.

If a contrapositive statement is true, then the contrapositive is true

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

if you need just tell me and i will come to the rescue.

step-by-step explanation: