24)The table represents some points on the graph of a linear function. Which function represents the same relationship? A) g(x) = 2x

B) g(x) = x - 3

C) g(x) = x - 8

D) g(x) = 2x - 8

25)Which system of equations could be used to solve for the point of intersection of the lines on the graph?

A) y = 3/4x + 1 and y = -4/3x + 9

B) y = 3/4x - 1 and y = -4/3x + 9

C) y = 3/4x - 1 and y = -3/4x = 9

D) y = 4/3x + 1 and y = -4/3x + 9

A) D) g(x) = 2x - 8

2) B) y = 3/4x - 1 and y = -4/3x + 9

Step-by-step explanation:

1)

In the table, we have the points

(5, 2)

(7, 6)

(9, 10)

(10, 12)

This seems to be a linear relationship, so let's try that:

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1)

If we use the first two points, we get the slope:

a = (6 - 2)/(7 - 5) = 4/2 = 2

if we use the first and last point, we get the slope:

a = (12 - 2)/(10 - 5) = 10/5 = 2

Then we can conclude that this is a linear relationship with a slope equal to 2.

y = 2*x + b

To find the value of b, we can just replace any of the points of the data table in the equation, for example, i will use the point (5, 2).

this means that x = 5, and  y = 2.

2 = 2*5 + b

2 = 10 + b

2 - 10 = b

-8 = b

Then the equation is:

y = 2*x - 8

the correct option is: D) g(x) = 2x - 8

2) Here we have two lines, notice that we can with just looking at the image, know the y-intercept of each line.

The one with a positive slope (grows to the right) has a y-intercept = - 1.

The one with a negative slope (grows to the left) has a y-intercept =  9.

The two options that match this condition are:

B) y = 3/4x - 1 and y = -4/3x + 9

C) y = 3/4x - 1 and y = -3/4x + 9

Where the only difference is the slope of the black line.

so et's check which slope matches that line.

In the graph we can see that it passes through the points:

(0, 9) and the point (6, 1)

Then the slope is:

a = (1 - 9)/(6 - 0) = -8/6 = -4/3

Then the correct option is where the negative slope is -4/3, that one is

B) y = 3/4x - 1 and y = -4/3x + 9

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

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part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).