Equations and Graphs of Rational Functions Precalculus 12 A car can travel 450 km in the same time it takes a train to travel 350 km. The car's average speed is 20 km/h faster than the average speed of the train. What is the average speed of the car? Give your answer to two decimal places.

I would just like help with figuring out the right equation for this word problem, because I cannot figure this out.

The average speed of the car is 90 km/h

Step-by-step explanation:

The rule of the distance id D = v × t, where

∵ A car can travel 450 km in the same time it takes a train to travel

   350 km

→ That means the time of them are equals

∴ Time of the car = Time of the train

→ From the rule above t =

∵ D(car) = 450 km and D(train) = 350 km

∵ The car's average speed is 20 km/h faster than the average speed

   of the train

→ Assume that the average speed of the train is x km/h

∴ v(train) = x km/h and v(car) = (x + 20) km/h

→ Use the rule of the time above to find the time of each one

∵ t(car) =

∵ t(train) =

∵ t(car) = t(train)

∴ =  

→ By using cross multiplication

∵ 450 × x = 350 × (x + 20)

∴ 450x = 350(x) + 350(20)

∴ 450x = 350x + 7000

→ Subtract 350x from both sides

∴ 100x = 7000

→ Divide both sides by 100 to find x

∴ x = 70

∵ x represents the average speed of the train

∴ The average speed of the train = 70 km/h

∵ The average speed of the car = x + 20

∴ The average speed of the car = 70 + 20

∴ The average speed of the car = 90 km/h

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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5104.38 inches

step-by-step explanation: