For each equation, determine whether it has no solutions, exactly one solution, or is true for all values of x (and has infinitely many solutions). If an equation has one solution, solve to find the value of x that makes the statement true. 6 x + 8 = 7 x + 13
6 x + 8 = 2 ( 3 x + 4 )
6 x + 8 = 6 x + 13

Step-by-step explanation:

We are given three equations to solve. First, let's solve the equations for x.

Equation 1

Therefore, we determined that for the first equation, x = -5. We can check our solution by substituting it back into the original equation.

Since we got a true statement, there are no other values of x for which we get a true statement. Let's test this with the opposite value: positive 5.

Therefore, for Equation 1, there is exactly one solution.

Equation 2

We get a true statement by solving for x (which ends up canceling out of the equation entirely). Therefore, we can check any value in place of x to see if we get a true statement. For this instance, I will use -3.

We still get a true statement, so Equation 2 has infinitely many solutions.

Equation 3

We get a false statement. Therefore, Equation 3 has no solution.

idk

step-by-step explanation:

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are