Consider the expression. 6 · 60 · 6–3 Which statements are true about the expression? Check all that apply. The 6 without an exponent is equivalent to the 6 having a 0 exponent. The sum of the exponents is

4. The expression has a value of 1/36 . True

5. An equivalent expression is (6)^5. (6)^- 7  True

Step-by-step explanation:

Not true. The 6 without an exponent is equivalent to the 6 having a 0 exponent.

6 · (6)^0 · (6)^–3

= 6.1.1/216

= 1/36

= (6)^-2

2. The sum of exponents is 2.  

False ( the sum of exponents is -2)

3.Multiply the exponents to solve the expression .

False when the bases are the same the exponents are added or subtracted.

4. The expression has a value of 1/36 .

True

5. An equivalent expression is (6)^5. (6)^- 7

True

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.