Send the from 18 to 23 with process in copy plz

22. l = 12m

b = 10m

Perimeter = 2(l + b)

= 2(12 + 10)

= 24 + 20

= 44m

Area = l×b

= 12 × 10

= 120m²

(a) Fencing required = 44m

Cost per metre = $12

Cost for the fencing of 44m = 12 × 44

= $528

(b) Levelling required = 120m²

Cost per metre² = $50

Cost for the levelling of 120m² = 120 × 50

= $6000

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: