Find the area of the triangle whose one angle measure is 55°, the other angle is a right angle and the side opposite the 55° angle is 15 units.

Step-by-step explanation:

Area of the right angles triangle will be expressed as;

Area of a triangle = 1/2base * height

Let the height of the triangle be 15 units

Get the base;

The base will be the adjacent;

Using the TOA trig identity;

tan 55 = opp/adj

tan 55 = 15/adj

adj = 15/tan 55

adj = 15/7.42

adj = 2.022 units

Area of the triangle = 1/2 * 15 * 2.022

Area of the triangle  = 15 * 1.011

Area of the triangle = 15.165units²

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

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so

step-by-step explanation:

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