The numbers 1 to 13 are written on 13 separate slips of paper and placed into a box. A slip of paper is randomly drawn from the box. Express probabilities as reduced fractions and as decimals rounded to 3 decimal places. 1. a. What is the probability that the slip of paper has an odd number on it? 1. b. What is the probability that the slip of paper has a number less than 4 on it? Theoretical probability can be used to predict the likelihood of an event. If a single, 6-sided die is rolled there are six possible outcomes. That is, after rolling the die, the side facing up will show one of six possibilities: 1, 2, 3, 4, 5, or 6. The theoretical probability that the die would land with a "2" on the side facing up is P = 1/6 = 0.167 because one out of the 6 possibilities is a "2." MGF2106 Project 2B; SP2020 5 2. Two experiments are conducted in which a single 6-sided die is rolled 20 and 80 times. The outcomes of the experiments are shown below. For each result calculate the experi

1a. 0.538

1b. 0.231

Step-by-step explanation:

For Section A.

Given data:

Numbers to be drawn = 1 to 13

Odd numbers = 7

Even numbers = 6

1a. Probability of drawing an odd number

= 7/13

= 0.538

1b. Probability of drawing a number less than 4.

= 3/13

= 0.231

Section B.

You need to provide me with the table containing the data, for me to be able to assist you with it.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.