Pls help me with this.

Explanation:

Focus on triangle HKL. This is a right triangle with the horizontal leg KL = 2. The vertical leg is the unknown side HK. The hypotenuse is HL shown by the single tickmark.

Triangle HKJ is also a right triangle. It shares the leg HK and the hypotenuse JH is congruent to HL as indicated by the single tickmark.

By the hypotenuse leg theorem, we can show that triangle HKL is congruent to triangle HKJ

From there, the corresponding pieces JK and KL must be the same length. So we can say JK = 2 because KL = 2.

Now use the segment addition postulate

GK = GJ + JK

GK = 7 + 2

GK = 9

Focus now on triangle GKH and triangle MKH. We can prove these are congruent triangles using the hypotenuse leg theorem. Here HK = HK as mentioned before; also, GH = HM due to the double tickmarks.

As you can probably guess by now, the hypotenuse leg theorem only applies to right triangles.

Since  triangle GKH is congruent to triangle MKH, we know that

GK = KM

Since GK = 9, this makes KM = 9.

Therefore,

GM = GK + KM

GM = 9 + 9

GM = 18

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x