Segement JK joins J (-2,4) and K (3,-1). Which point is four times as far from K as it is from J?

P( - 1, 3)

Step-by-step explanation:

J(- 2, 4), P(x, y), K(3, -1)

KP = 4JP and KP + JP = JK

5JP = JK

JP = JK

JK = 5√2

JP = √2

KP = 4√2

2 = (x + 2)² + (y - 4)²

32 = (x - 3)² + (y + 1)²

P( - 1, 3)

8 apples are left.

step-by-step explanation:

10-2=8

10 apples

take 2

now u have 8

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.