X^2+6x-16=0
quadratic equation

x = - 8, x = 2 are the solutions

Step-by-step explanation:

Given

x² + 6x - 16 = 0

Consider the factors of the constant term (- 16) which sum to give the coefficient of the x- term (+ 6)

The factors are + 8 and - 2 , since

8 × - 2 = - 16 and 8 - 2 = + 6 , thus

(x + 8)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 8 = 0 ⇒ x = - 8

x - 2 = 0 ⇒ x = 2

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

y=mx+b

step-by-step explanation:

m slope

b y-intercept