Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Upper H 0: pequals0.6 versus Upper H 1: pgreater than0.6 nequals200; xequals135, alphaequals0.05 Is np 0 (1 minus p 0 )greater than or equals10. Use technology to find the P-Value.

Step-by-step explanation:

From the given information:

The null and the alternative hypothesis can be well written as:

Given that:

n = 200

x = 135

Alpha ∝ = 0.05 level of significance

Then;

⇒

= 200 × 0.6 × (1 -0.6)

= 200 × 0.6 × 0.4

= 48 ≥ 10

The sample proportion

= 0.675

The test statistics

Z = 2.165

The P-value = P(Z > 2.165)

= 1 - P(Z < 2.165)

From the z tables

= 1 - 0.9848

= 0.0152

Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).

Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6

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