A parallelogram with coordinates A (-2,3), B (3,3), C (4,6), and D(-1,6) is the first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D what is the distance, in units between point C' and point D' in the resulting figure

Given:

The vertices of a parallelogram are A (-2,3), B (3,3), C (4,6), and D(-1,6).

It is first rotated 90 degrees clockwise and then translated 4 units left and 2 units down to form quadrilateral A'B'C'D.

To find:

The distance between C' and D'.

Solution:

If a figure rotated 90 degrees clockwise, then

If figure translated 4 units left and 2 units down, then

Distance formula:

Distance between C'(2,-6) and D'(2,-1) is

Therefore, the distance between C'D' is 5 units.

21/58.

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let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.