If a ship travels north for 18 miles and east for 12 miles, to the nearest tenth, approximately how far away is it
from it's starting point?

The ship is approximately 21.6 miles away from its starting point

Step-by-step explanation:

∵ The North and the East are perpendicular

→ That means the distance between the starting position and

   the ending position shows a hypotenuse of a right triangle which

   its legs are the distances due to North and East

∵ The ship travels north for 18 miles

∴ leg1 = 18 miles

∵ The ship travels east for 12 miles

∴ leg2 = 12 miles

→ By using Pythagoras Theorem

∵ (hypotenuse)² = (leg1)² + (leg2)²

∴ (hypotenuse)² = (18)² + (12)²

∴ (hypotenuse)² = 324 + 144

∴ (hypotenuse)² = 468

→ Take √  for both sides

∴ hypotenuse = 21.63330765

→ Approximate it to the nearest tenth

∴ hypotenuse = 21.6 miles

∵ The hypotenuse of the right triangle represents the distance from

   the starting position to the ending position

∴ The ship is approximately 21.6 miles away from its starting point

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m