Write the equation of a line passing through the given point that is perpendicular to the given line. 3.x – 8y = 16; (-3, 1)

-8x-21=3y or -8/3x-7=y or 8x+y+21=0

Step-by-step explanation:

First find the slope of 3x-8y=16.

3x-16=8y (divide both sides by 8 so that y is isolated)

3/8x-2=y The slope is 3/8. The perpendicular slope is the negative reciprocal of 3/8, which is -8/3

Using the points, the equation of the line can be found.

(-8/3=y-1/x-(-3))3(x-(-3) (3(x-(-3) is the common denominator

This equals -8x-24=3y-3, add three to both sides which equals -8x-21=y.

The other answers are written in slope y-intercept form and general form.

*Note: x-(-3) can be written as x+3

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right