Pls can someone help me factorise: 4u²‐u-3

(u - 1)(4u + 3)

Step-by-step explanation:

Given

4u² - u - 3

Consider the factors of the product of the coefficient of the u² term and the constant term which sum to give the coefficient of the u- term.

product = 4 × - 3 = - 12 and sum = - 1

The factors are -  4 and + 3

Use these factors to split the u- term

4u² - 4u + 3u - 3 ( factor the first/second and third/fourth terms )

= 4u(u - 1) + 3(u - 1) ← factor out (u - 1) from each term

= (u - 1)(4u + 3)

Thus

4u² - u - 3 = (u - 1)(4u + 3) ← in factored form

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1