If 12 g of a radioactive substance are present initially and eight years later only 6 g remain, how much of the substance will be present after 11 years

4.083g

Step-by-step explanation:

12 g of a radioactive substance are present initially and eight years later only 6 g remain, how much of the substance will be present after 11 years

Starting with half life, we want to find k.

In a 4 year period, t=8 and A quantity will be reduced to (1/2)*A.

(1/2)= e^k8

In(1/2)

a. the are of the rectangle is 18.25

b. 18.25 times two is 36.50

rae me : d

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44