In Exercises 1-3, graph AABC and its image after a reflection in the given line. 1. A(0, 2), B(1, -3), C(2, 4); x-axis
1.
2. A(-2,-4), B(6,2), C(3. – 5); y-axis
3. A(4, -1), B(3, 8), C(-1, 1); y = -2

1. Point A: (0, 2)

Point B: (-1, -3)

Point C: (-2, 4)

2. Point A: (-2, 4)

Point B: (6, -2)

Point C: (3, 5)

3. Point A: (4, -3)

Point B: (3, -12)

Point C: (-1, -5)

Step-by-step explanation:

1.

Reflection of point A:

Reflections over the x-axis are really easy. All you have to do is change the x-coordinate to the opposite sign.

In this case, 0 does not need to change since it already lies on the x-axis.

The coordinate for A will stay the same as (0, 2).

Reflection of point B:

Again, change the x-coordinate to negative.

1 → -1

The coordinate for B will now be (-1, -3).

Reflection of point C:

2 → -2

The coordinate for C will now be (-2, -4).

2.

Reflection of point A:

Reflections over the y-axis are also really easy. This time, all you have to do is change the y-coordinate to the opposite sign.

In this case, -4 would change to just 4.

The coordinate for A will stay the same as (2, 4).

Reflection of point B:

Again, change the y-coordinate to negative.

2 → -2

The coordinate for B will now be (6, -2).

Reflection of point C:

-5 → 5

The coordinate for C will now be (-1, 5).

3.

This is going to be a bit harder than the previous two, but I know you can handle it. :)

Reflection of point A:

The x will stay the same and only the y will change.

Take the y-coordinate and subtract it from the reflection line while getting the absolute value..

|(-1) - (-2)| = |1| = 1

This means, point A is one unit down the line y = -2

(-2) - 1 = -3

The coordinate for A will now be (4, -3).

Reflection of point B:

Again, the x will stay the same and only the y will change.

Using the absolute value, get the y-coordinate and subtract it from the reflection line again..

|(8) - (-2)| = |10| = 10

This means, point A is five unit down the line y = -2

(-2) - 10 = -17

The coordinate for B will now be (3, -12).

Reflection of point C:

I think you get the gist of it.

|(1) - (-2)| = |3| = 3

(-2) - 3 = -5

The coordinate for C will now be (-1, -5).

The red triangle is the original image and the blue triangle is the image after the reflection. The purple line is the reflection line.

Hope this helped!

i understand 100% 10/10 hit or miss?

step-by-step explanation:

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers