I sell cookies for $3 and muffins for $7. Yesterday, I made $129. I sold a total of 27 items. How many of each did I sell? CAN SOMEONE ANSWER IT PLZ

9514 1404 393

Step-by-step explanation:

Often, you can work these problems in your head.

If you sold all cookies, your revenue would have been 27×3 = 81. It was 129-81 = 48 more than that. Each muffin generates 4 more revenue than a cookie dies, so there must have been 48/4 = 12 muffins. The 27-12 = 15 were cookies.

You sold 15 cookies and 12 muffins.

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If you let a variable represent the most expensive item (m for muffins), then you can write an equation for the revenue. You may recognize that some of the steps in the solution match the "verbal" solution above.

  3(27 -m) +7m = 129

  4m +81 = 129

  4m = 129 -81 = 48

  m = 48/4 = 12 . . . muffins

  27-12 = 15 . . . cookies

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

entering that problem on the tube might get you an answer