Titus is asked to prove hexagon FEDCBA is congruent to hexagon F'E'D'C'B'A' in the graph below. Titus thinks that if he transforms hexagon
FEDCBA by (x, y) - (x + 16. y - 10) he can show the two figures are
congruent. Is he correct? Explain why or why not. If Titus is incorrect, what
series of transformations will correctly prove FEDCBA F'E'D'C'B'A'S
у
6
В.
>E
4
2
с
D
-14 -12 -10 -8
x
-6
4
2
4
6
8
10 12
-20
-2
in
A'
4
E!
-6
В"
-8
lo
c
-10
Is Titus correct? YES NO
Explain why or why not (required)

correct

Step-by-step explanation:

he is correct because the transformation is a translation and under the translation the image and preimage are congruent.

the measure of the sides are preserved, and the peasure of the angles are preserved so if all the corsponding sides and angles are congruent the hexagons are congruent too

(x, y) > ( - x , y - 10 )

Step-by-step explanation:

Titus is not correct.

There are two transformations will correctly prove FEDCBA ≅ F'E'D'C'B'A'

First transformation is Reflection over y-axis , then translation 10 units down.

The final formula is ( - x , y - 10 )

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.